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Extra info for Cracking the AP physics B exam
Time graph is given: How far did the object travel during a particular time interval? For example, let’s figure out the displacement of the object from time t = 4 s to time t = 6 s. During this time interval, the velocity was a constant −5 m/s, so the displacement was ∆x = v∆t = (−5 m/s)(2 s) = −10 m. Geometrically, we’ve determined the area between the graph and the horizontal axis. After all, the area of a rectangle is base × height and, for the shaded rectangle shown below, the base is ∆t, and the height is v.
The graders will not score crossed-out work. And, as we mentioned before, partial solutions may receive partial credit, so you should definitely show all your work, especially since correct answers without supporting work may lose credit. This is particularly true when you are asked to “justify” your answer, as graders are looking for some evidence of how you arrived at your solution. Finally, make sure that all of your numerical answers are in the appropriate units. Sample test questions are also available directly from the College Board.
For example, the average velocity from 0 to 10 seconds is 50 m/s. The instantaneous velocity at 10 seconds was 100 m/s, or twice the average velocity of 50 m/s. Again, these shortcuts are only true for objects that start from rest and have a constant acceleration. -time graph: What does this graph tell us? It says that, at time t = 0, the object’s velocity was v = 0. Over the first two seconds, its velocity increased steadily to 10 m/s. At time t = 2 s, the velocity then began to decrease (eventually becoming v = 0, at time t = 3 s).